16)
molality = number of moles of solute / mass of solvenet in Kg
= 0.755/1.75
= 0.=431 m
17)
molality = number of moles of solute / mass of solvenet in Kg
0.66 = 0.15 / mass of solvenet in Kg
mass of solvenet in Kg = 0.227 Kg
mass of solvent= 227 g
mass of solute = number of moles * molar mass
= 0.15*80.04
= 12
mass of solution = 227 g + 12 g = 239 g
Answer: b
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