A tank fo water at 2.0atm is compressed till it reaches 10.5atm. If the orginal temperature...
A tank fo water at 2.0atm is compressed till it reaches 10.5atm. If the orginal temperature of the water vapor was 115 degrees C what is the new temp? Is it Boyles, Charles or Gay-Lussac's law and solve it.
Homework Answers
This will e solved by the Gay-Lussac's law P1/T1= P2/T2 or T2 = P2T1/P1
here P1 = 2 atm P2 = 10.5 atm T1= 115 C+273.15=388.15 K ; T2 = ?
using the values
T2= 10.5*388.15/2= 2037.78 K = 1764.63 degree C
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