Question

A sports car is advertised to have a maximum cornering acceleration of 0.85 g. What is the maximum speed that the car can go around a curve with a 100-m radius? What is its maximum speed for a 50-m radius curve? If wet pavement reduces its maximum cornering acceleration to 0.6g, what do the answers to (a) and (b) become?
I need some help with this problem

Answer 1

a) We know, v^2 /r = centripetal acceleration a

V = sqrt(ar)

              = sqrt(0.85*9.8*100)

     = 28.86 m/s

b) v = sqrt(0.85*9.8*50)

          = 20.41 m/s

c)    (A)   v = sqrt(0.6*9.8*100) = 24.25 m/s

     (B) v = sqrt(0.6*9.8*50) = 17.15 m/s