calculate probabilities to find 0 sick patients, 1 sick patient,2 3,4 and 5 sick patients among the group of 3000 coil miners, if the probability of the disease is 0.001 . create the diagram p(m) versus m. calculate the mean and show its position on the diagram
Ans:
Given that
n=3000 and p=0.001
Approximate to Poisson distribution:
lambda=np=3000*0.001=3
p(m)=(m,3,false)
m | p(m) |
0 | 0.050 |
1 | 0.149 |
2 | 0.224 |
3 | 0.224 |
4 | 0.168 |
5 | 0.101 |
mean for above data=0*0.050+1*0.149+2*0.224+3*0.224+4*0.168+5*0.101
=2.45
calculate probabilities to find 0 sick patients, 1 sick patient,2 3,4 and 5 sick patients among...
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