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The rate coefficient of a chemical reaction is studied as a function of temperature, and the...
The rate data of the reaction was collected at different temperatures (°C) and functions of the...
The rate data of the reaction was collected at different temperatures (°C) and functions of the data plotted to determine the activation energy. 18 17 T 16.5 36.2 47.7 57.3 k 9.86 x 104 2.01 x 106 9.84 x 106 3.41 x 107 16 y = (-1.37 x 10^)x + 58.8 15 14 13 12 = 11 10 0.0030 0.0031 0.0032 0.0033 0.0034 0.0035 1. Clearly label the x and y axes (above) with the proper function. 2. Determine Ea...
A series of experiments were conducted where the equilibrium constant (K) was determined at various temperatures...
A series of experiments were conducted where the equilibrium constant (K) was determined at various temperatures (T). The data was then graphed (shown below). The equation of the line is listed on the graph. Use the graph to determine AH° (in kJ/mol). -30 0.0031 0.0032 0.0033 0.0034 0.0035 0.0036 0.0037 -30.50.003 -31 y = -6861.2x - 9.2495 -31.5 -32 -32.5 In -33 -33.5 -34 -34.5 -35 1/T in K
Examine the graph below and determine the value of the energy of activation for the chemical...
Examine the graph below and determine the value of the energy of activation for the chemical process. 0 -1 y=-11624x + 32.055 R² = 1 -2 In k -5 -6 0.0028 0.0029 0.0032 0.0033 0.003 0.0031 1/T (1/K) +96654 J/mol -11624 J/mol +32.055 J/mol -32.055 J/mol -96654 J/mol +11624 J/mol
Examine the graph below and determine the value of the energy of activation for the chemical...
Examine the graph below and determine the value of the energy of activation for the chemical process. 0 y=-11624x + 32.055 R2 = 1 2 In k -3 -5 -6 0.0028 0.0029 0.0032 0.0033 0.003 0.0031 1/T (1/K) -96654 J/mol +96654 J/mol - 11624 J/mol +11624 J/mol -32.055 J/mol +32.055 J/mol
Examine the graph below and determine the value of the energy of activation for the chemical...
Examine the graph below and determine the value of the energy of activation for the chemical process. 0 -1 y = -11624x + 32.055 R2 = 1 -2 In k 3 -4 -5 -6 0.0028 0.0029 0.003 0.0031 0.0032 0.0033 1/T (1/K) -32.055 J/mol +32.055 J/mol -96654 J/mol +11624 J/mol - 11624 J/mol +96654 J/mol
Question 4 2 pts You generate the below Arrhenius plot of your data. Determine the activation...
Question 4 2 pts You generate the below Arrhenius plot of your data. Determine the activation energy of the reaction in kJ/mol. Note: R = 8.314 J/(mol*K) = 0.008314 kJ/(mol*K) = 0.0821 L*atm/(mol*K) Arrhenius Plot: Sample Data o e đ d c In(k) đ ở s y = -18808x + 56.183 R2 = 0.976 do o o 0.0032 0.00325 0.0033 0.00335 0.0034 0.00345 1/T
Temp k 0 °C 6.6667 x 10-5 28°C 2.0560 x 10-4 35°C 9.6155 x 10-4
Temp
k
0 °C
6.6667 x 10-5
28°C
2.0560 x 10-4
35°C
9.6155 x 10-4
It is not practicable to measure the intercept directly at 1/T-0, so calculate In A from the measured slope and the coordinates of any point on the graph. Compare your values of E and A with those obtained by previous students, namely E-52 kJ mol 1 and A- ~10 dm mol-1 s1 For E-45.3953 kJ mole equation: y -5460.1 x + 10.272- At 273K, 301K...
It is not practicable to measure the intercept directly at 1/T=0, so calculate ln A from the meas...
It is not practicable to measure the intercept directly at
1/T=0, so calculate ln A from the measured slope and the
coordinates of any point on the graph. Compare your values of E and
A with those obtained by previous students, namely E = 52 kJ
mol-1 and A = ~107 dm3
mol-1 s-1
For E = 45.3953 kJ mol-1
equation: y = -5460.1x + 10.272
At 273K, 301K and 308K, I calculate the A, but it's ~3 x
10-3...
Please answer questions 1 and 2 on The rate constant for the reaction answered A +...
Please answer questions 1 and 2
on The rate constant for the reaction answered A + B->C out of 1.0 is 4.1 x104 U(mol s) at 593 K. The activation energy is 101 kj/mol. question Determine the temperature when the rate constant is 1.2 x10-3 L/(mol s)- Answer: 2 One (often inaccurate) rule of thumb in biology is that a 10 °C change increases the rate by a factor of ten. If the lower temperature is 3 °C, what activation...
The hypothetical reaction A(g)+B(g)->C(g)+D(g) was studied in order to determine its activation energy. The appropriate data...
The hypothetical reaction A(g)+B(g)->C(g)+D(g) was studied in
order to determine its activation energy. The appropriate data was
collected, analyzed, and graphed to produce the following graph.
Use the graph below to answer the questions:
a)What is the correct label for the x-axis
b)What is the correct label for the y-axis
c)What is the activation energy, in Kj/mol, for this
reaction?
Linear Fit for: Data Set IY y=mxeb m (Slope): -1435 [Y-intercept): 28.07 Correlation: -0.9970 RMSE: 0.1183 0.005 0.0045 0.004 0.0035
The rate data of the reaction was collected at different temperatures (°C) and functions of the data plotted to determine the activation energy. 18 17 T 16.5 36.2 47.7 57.3 k 9.86 x 104 2.01 x 106 9.84 x 106 3.41 x 107 16 y = (-1.37 x 10^)x + 58.8 15 14 13 12 = 11 10 0.0030 0.0031 0.0032 0.0033 0.0034 0.0035 1. Clearly label the x and y axes (above) with the proper function. 2. Determine Ea...
A series of experiments were conducted where the equilibrium constant (K) was determined at various temperatures (T). The data was then graphed (shown below). The equation of the line is listed on the graph. Use the graph to determine AH° (in kJ/mol). -30 0.0031 0.0032 0.0033 0.0034 0.0035 0.0036 0.0037 -30.50.003 -31 y = -6861.2x - 9.2495 -31.5 -32 -32.5 In -33 -33.5 -34 -34.5 -35 1/T in K
Examine the graph below and determine the value of the energy of activation for the chemical process. 0 -1 y=-11624x + 32.055 R² = 1 -2 In k -5 -6 0.0028 0.0029 0.0032 0.0033 0.003 0.0031 1/T (1/K) +96654 J/mol -11624 J/mol +32.055 J/mol -32.055 J/mol -96654 J/mol +11624 J/mol
Examine the graph below and determine the value of the energy of activation for the chemical process. 0 y=-11624x + 32.055 R2 = 1 2 In k -3 -5 -6 0.0028 0.0029 0.0032 0.0033 0.003 0.0031 1/T (1/K) -96654 J/mol +96654 J/mol - 11624 J/mol +11624 J/mol -32.055 J/mol +32.055 J/mol
Examine the graph below and determine the value of the energy of activation for the chemical process. 0 -1 y = -11624x + 32.055 R2 = 1 -2 In k 3 -4 -5 -6 0.0028 0.0029 0.003 0.0031 0.0032 0.0033 1/T (1/K) -32.055 J/mol +32.055 J/mol -96654 J/mol +11624 J/mol - 11624 J/mol +96654 J/mol
Question 4 2 pts You generate the below Arrhenius plot of your data. Determine the activation energy of the reaction in kJ/mol. Note: R = 8.314 J/(mol*K) = 0.008314 kJ/(mol*K) = 0.0821 L*atm/(mol*K) Arrhenius Plot: Sample Data o e đ d c In(k) đ ở s y = -18808x + 56.183 R2 = 0.976 do o o 0.0032 0.00325 0.0033 0.00335 0.0034 0.00345 1/T
Temp
k
0 °C
6.6667 x 10-5
28°C
2.0560 x 10-4
35°C
9.6155 x 10-4
It is not practicable to measure the intercept directly at 1/T-0, so calculate In A from the measured slope and the coordinates of any point on the graph. Compare your values of E and A with those obtained by previous students, namely E-52 kJ mol 1 and A- ~10 dm mol-1 s1 For E-45.3953 kJ mole equation: y -5460.1 x + 10.272- At 273K, 301K...
It is not practicable to measure the intercept directly at
1/T=0, so calculate ln A from the measured slope and the
coordinates of any point on the graph. Compare your values of E and
A with those obtained by previous students, namely E = 52 kJ
mol-1 and A = ~107 dm3
mol-1 s-1
For E = 45.3953 kJ mol-1
equation: y = -5460.1x + 10.272
At 273K, 301K and 308K, I calculate the A, but it's ~3 x
10-3...
Please answer questions 1 and 2
on The rate constant for the reaction answered A + B->C out of 1.0 is 4.1 x104 U(mol s) at 593 K. The activation energy is 101 kj/mol. question Determine the temperature when the rate constant is 1.2 x10-3 L/(mol s)- Answer: 2 One (often inaccurate) rule of thumb in biology is that a 10 °C change increases the rate by a factor of ten. If the lower temperature is 3 °C, what activation...
The hypothetical reaction A(g)+B(g)->C(g)+D(g) was studied in
order to determine its activation energy. The appropriate data was
collected, analyzed, and graphed to produce the following graph.
Use the graph below to answer the questions:
a)What is the correct label for the x-axis
b)What is the correct label for the y-axis
c)What is the activation energy, in Kj/mol, for this
reaction?
Linear Fit for: Data Set IY y=mxeb m (Slope): -1435 [Y-intercept): 28.07 Correlation: -0.9970 RMSE: 0.1183 0.005 0.0045 0.004 0.0035
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