![Knowing that the standard reduction potential, E half-cell is +0.34V of the CujCu(s) (or knowing that the standard oxidation potential, Eoo of the Cu(s)]Cu* or knowing that the standard oxidation potential, E )u half-cell is -0.34 V), what is the potential of the nickel half-cell? Is this Ed or E hat is the potential of the nickel half-cell? Is this E, or E. red 8. What is the standard reduction potential (SRP, Eond) of the Ni2 |Ni(s) halfcell? What is the standard reduction potential (SRP, E,) of the Ni Ni(s) half-cell? (Hint: This is the value from part f with either the same or opposite sign.)](http://img.homeworklib.com/questions/47a18870-bc55-11eb-9a89-0170eeff7a18.png?x-oss-process=image/resize,w_560)
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Knowing that the standard reduction potential, E half-cell is +0.34V of the Cu'jCu(s) (or knowing that...
3. A student connects a Cd?"(0.20 M)|Cd(s) half-cell to a Cu?"(1 M) Cu(s) electrode. When the...
3. A student connects a Cd?"(0.20 M)|Cd(s) half-cell to a Cu?"(1 M) Cu(s) electrode. When the red lead is attached to the Cu electrode, the cell potential read by the voltmeter, E is +0.77 V. a. What is the reduction half-reaction at the cathode (red lead)? b. What is the oxidation half-reaction at the anode (black lead)? c. What is the overall cell reaction? d. Write the expression for the thermodynamic reaction quotient, Q, and calculate its value for this...
Standard reduction potentials for nickel(II) and copper(II) The standard reduction potential for a substance indicates how...
Standard reduction potentials for nickel(II) and copper(II) The standard reduction potential for a substance indicates how readily that substance gains electrons relative to other substances at standard conditions. The more positive the reduction potential, the more easily the substance gains electrons. Consider the following: Ni2+(aq)+2e−→Ni(s),Cu2+(aq)+2e−→Cu(s), E∘red=−0.230 V E∘red=+0.337 V What is the standard potential, E∘cell, for this galvanic cell? Use the given standard reduction potentials in your calculation as appropriate. Express your answer to three decimal places and include the...
First fill in your half cell and cell reactions. F in standard cell potentials as you...
First fill in your half cell and cell reactions. F in standard cell potentials as you calculate them. Oxidation at the Anode: The black (.) lead is attached to the electrode, which is the source of electrons. Write the anode half reaction: Reduction at the Cathode: The red lead (+) is attached to the electrode. Write the cathode half reaction: E degree - V. Overall Cell Reaction (Net Ionic equation): Write the overall cell reaction (balance electrons and add together):...
The reduction potential for the following non-standard half cell at 298K is volts. 24+ (1.83x10-3M) +...
The reduction potential for the following non-standard half cell at 298K is volts. 24+ (1.83x10-3M) + 2e —>H2 (1.68atm) The reduction potential for the following non-standard half cell at 298K is volts. Al3+ (4.93x10-*M)+ 3e —AI (S) What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the F2 pressure is 6.44x10 atm, the F concentration is 1.41M, and the Ni2+ concentration is 1.28M? F2(g) + Ni(s)— 2F" (aq) +...
E) If the cell potential as measured is 1.04 volts, what would be the reduction potential associa...
Please give the correct answer for (e) the last problem
e) If the cell potential as measured is 1.04 volts, what would be the reduction potential associated with the Ni2+/Ni reaction if the Hg/Flg22+ half-cell is assigned a potential of 0.00 V? Repeat the question: if the Hg/Hg22" half-cell is assigned a reduction potential of -0.80 volts? Hg/Hg2 is 0.00 v: Hg/Hg22* is -0.80 V:
e) If the cell potential as measured is 1.04 volts, what would be the reduction...
Given the following standard reduction potentials choose the cell which will work as a voltaic cell....
Given the following standard reduction potentials choose the cell which will work as a voltaic cell. All cells below are written according to the usual cell diagram convention. Cu2+(aq) + 2e → Cu(s) E° = 0.34 V 2H+(aq) + 2e → H2(g) E° = 0.00 V Sn2+ (aq) + 2e → Sn(s) E° = -0.14 V Ni2+(aq) + 2e → Ni(s) E° = -0.26 V Cd2+(aq) + 2e → → Cd(s) E° = -0.40 V Sn(s) | Sn2+(aq) || Ni2+(aq)...
Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is...
Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is related to the standard cell potential, Ecel, by the equation Reduction half-reaction (V) Ag+ (aq) + e-→Ag(s) Cu2+ (aq) + 2e-→Cu(s) 0.34 Sn (a) 4e-Sn(s 0.15 2H' (aq) + 2e-→H2 (g) Ni2+ (aq) + 2e-→Ni(s)-0.26 Fe2+ (aq) + 2e-→Fe(s)-0.45 Zn2+ (aq) + 2e-→Zn(s)-0.76 Al3+ (aq) +3e-→Al(s) -1.66 Mg2+ (aq) + 2e-→Mg(s) -2.37 0.80 n FEcell where n is the number of moles of electrons...
Selective Reduction The standard reduction potential for the half-reaction: Sn4+ + 2e - Sn2+ is +0.15...
Selective Reduction The standard reduction potential for the half-reaction: Sn4+ + 2e - Sn2+ is +0.15 V. Consider data from the table of standard reduction potentials for common half-reactions, in your text. For a galvanic cell under standard conditions, which of the following anodic half reactions would produce, at the cathode a spontaneous reduction of Sn4+ to Sn2+ but not Sn2+ to Sn. no yes yes yes yes yes Fe — Fe2+ + 2e- Sn2+ Sn4+ + 2e- Sn Sn2+...
4. A galvanic cell is composed of these two half-cells, with the standard reduction potentials shown:...
4. A galvanic cell is composed of these two half-cells, with the standard reduction potentials shown: Cu2+(aq) + 2e Cu(s) Fe3+(aq) + 3e,-- Fe(s) +0.34V +0.77V What is the standard free energy change for the cell reaction of this galvanic cell?
Selective Oxidation The standard reduction potential for the half-reaction Sn4+ + 2e - Sn2+ is +0.15...
Selective Oxidation The standard reduction potential for the half-reaction Sn4+ + 2e - Sn2+ is +0.15 V. Consider data from the table of standard reduction potentials for common half-reactions, in your text. For a galvanic cell under standard conditions, which of the following cathodic half reactions would produce, at the anode, a spontaneous oxidation of Sn to Sn2+ but not Sn2+ to Sn4+. 2H+ + 2e - H2 Fe3+ + 3e + Fe Sn2+ + 2e Fe2+ + 2e →...
3. A student connects a Cd?"(0.20 M)|Cd(s) half-cell to a Cu?"(1 M) Cu(s) electrode. When the red lead is attached to the Cu electrode, the cell potential read by the voltmeter, E is +0.77 V. a. What is the reduction half-reaction at the cathode (red lead)? b. What is the oxidation half-reaction at the anode (black lead)? c. What is the overall cell reaction? d. Write the expression for the thermodynamic reaction quotient, Q, and calculate its value for this...
First fill in your half cell and cell reactions. F in standard cell potentials as you calculate them. Oxidation at the Anode: The black (.) lead is attached to the electrode, which is the source of electrons. Write the anode half reaction: Reduction at the Cathode: The red lead (+) is attached to the electrode. Write the cathode half reaction: E degree - V. Overall Cell Reaction (Net Ionic equation): Write the overall cell reaction (balance electrons and add together):...
The reduction potential for the following non-standard half cell at 298K is volts. 24+ (1.83x10-3M) + 2e —>H2 (1.68atm) The reduction potential for the following non-standard half cell at 298K is volts. Al3+ (4.93x10-*M)+ 3e —AI (S) What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the F2 pressure is 6.44x10 atm, the F concentration is 1.41M, and the Ni2+ concentration is 1.28M? F2(g) + Ni(s)— 2F" (aq) +...
Please give the correct answer for (e) the last problem
e) If the cell potential as measured is 1.04 volts, what would be the reduction potential associated with the Ni2+/Ni reaction if the Hg/Flg22+ half-cell is assigned a potential of 0.00 V? Repeat the question: if the Hg/Hg22" half-cell is assigned a reduction potential of -0.80 volts? Hg/Hg2 is 0.00 v: Hg/Hg22* is -0.80 V:
e) If the cell potential as measured is 1.04 volts, what would be the reduction...
Given the following standard reduction potentials choose the cell which will work as a voltaic cell. All cells below are written according to the usual cell diagram convention. Cu2+(aq) + 2e → Cu(s) E° = 0.34 V 2H+(aq) + 2e → H2(g) E° = 0.00 V Sn2+ (aq) + 2e → Sn(s) E° = -0.14 V Ni2+(aq) + 2e → Ni(s) E° = -0.26 V Cd2+(aq) + 2e → → Cd(s) E° = -0.40 V Sn(s) | Sn2+(aq) || Ni2+(aq)...
Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is related to the standard cell potential, Ecel, by the equation Reduction half-reaction (V) Ag+ (aq) + e-→Ag(s) Cu2+ (aq) + 2e-→Cu(s) 0.34 Sn (a) 4e-Sn(s 0.15 2H' (aq) + 2e-→H2 (g) Ni2+ (aq) + 2e-→Ni(s)-0.26 Fe2+ (aq) + 2e-→Fe(s)-0.45 Zn2+ (aq) + 2e-→Zn(s)-0.76 Al3+ (aq) +3e-→Al(s) -1.66 Mg2+ (aq) + 2e-→Mg(s) -2.37 0.80 n FEcell where n is the number of moles of electrons...
Selective Reduction The standard reduction potential for the half-reaction: Sn4+ + 2e - Sn2+ is +0.15 V. Consider data from the table of standard reduction potentials for common half-reactions, in your text. For a galvanic cell under standard conditions, which of the following anodic half reactions would produce, at the cathode a spontaneous reduction of Sn4+ to Sn2+ but not Sn2+ to Sn. no yes yes yes yes yes Fe — Fe2+ + 2e- Sn2+ Sn4+ + 2e- Sn Sn2+...
4. A galvanic cell is composed of these two half-cells, with the standard reduction potentials shown: Cu2+(aq) + 2e Cu(s) Fe3+(aq) + 3e,-- Fe(s) +0.34V +0.77V What is the standard free energy change for the cell reaction of this galvanic cell?
Selective Oxidation The standard reduction potential for the half-reaction Sn4+ + 2e - Sn2+ is +0.15 V. Consider data from the table of standard reduction potentials for common half-reactions, in your text. For a galvanic cell under standard conditions, which of the following cathodic half reactions would produce, at the anode, a spontaneous oxidation of Sn to Sn2+ but not Sn2+ to Sn4+. 2H+ + 2e - H2 Fe3+ + 3e + Fe Sn2+ + 2e Fe2+ + 2e →...
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