Chapter 27, Problem 063 In the circuit of the figure 8 = 2.30 kV, C =...

Question

Question

Chapter 27, Problem 063 In the circuit of the figure 8 = 2.30 kV, C = 8.10 pF, R1 = R2 = R3 = 0.970 MO. With C completely unc

Answer 1

Answer #1

At t-o, apacitor behave as Short circuit, At t=2, Gpacitor behives as open circuit. E = 2300 V C= 8.1 MF RIF R2 = R₂ = 0.97 M

Answer 2

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