how many ml of commercial HCL are required to prepare 2.5 L of a 1.25 N solution for the analysis of crude fiber in leafy vegetables
commercial HCl normality = 11.65 N
volume = V1 = ?
N2 = 1.25 N
V2 = 2.5 L
N1 V1 = N2 V2
11.65 x V1 = 1.25 x 2.5
V1 = 0.268 L
V1 = 268 mL
volume of commercial HCl normality needed = 268 mL
how many ml of commercial HCL are required to prepare 2.5 L of a 1.25 N...
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