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2. Determine the poH Mo two decimal places) of the solution that is produced by mixing 766 mL of 2.18x10-M Nal with 13.8 mL o

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13.8mL, 5.45 X16m mgH, 766 m L,2:18X16 m NqH, we get ealy one Ht, mote of Ht = 766 X163x2:18X15 Here we get 2Ht. Here - 2(1THt]= M otes volume 0.1689 0• 2159. %3D 779.8X103 PH= -log On t], PH +poH= 19 (weknow %3D PH z 0.665 pon 214- pM poH 14 6.665

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