Question

A neodymium-glass laser emits short pulses of high-intensity electromagnetic waves. The electric field of such a wave has an rms value of E 2.0 x 109 NIC. Find the average power of each pulse that passes through a 1.6 x 10-5-m2 surface that is perpendicular to the laser beam.

A neodymium-glass laser emits short pulses of high-intensity electromagnetic waves. The electric field of such a wave has an rms value of Erms = 2.0 × 109 N/C. Find the average power of each pulse that passes through a 1.6 × 10-5-m2 surface that is perpendicular to the laser beam.

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Answer #1

The max value of electric fieldis, Ev=v2 Ermita = (2.0x10 N/C) =2.82x10°NIC The value of the average power of the each pulse

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