Question

NUCLEAR PHYSICS

COMPUTE THE MOMENT OF INERTIA OF THE ROTATING NUCLEUS 174-Hf AND BY USING THE ROTATIONAL ENERGY EQUATION SHOW THAT YOU GET ENERGIES THAT FIT THE EXPERIMENTAL DATA (BELOW)

Erot = l(l+1)hbar^2/(2MoI)

Where MoI means Moment of Inertia

Radius of 174-Hf: 159 pm.

E(0+) E(2+) E(4+) E(6) E(8+) E(10+) E(12+) 0 0.091 0.297 0.608 1.010 1.486 2.021 Band 1

Answer 1

From liquid dop model No ta tio nal engy &vela tue Nucdus J) EJ 21 xperimen tal Data Now tue E(21) 09 N1 E (1") -484 2(2.1) I 2(211) E(2) 2E (2') 2r G K G.626 AL0-3 091x106 2 -36 g-in 3x6.626X6 62l 2 .6x16x.691 -36 hg-h 282.7 X(0 Jt we taus, () 1.436 Mev 1o (lo1) 2X1.u860 (10 x /6.626 K(6-24 -6 K10-19 2 X 5S XL.626 X6.426 36 X 1-6 X1.6 X .486 - 36 - n 634.95 X10 We cam taue the averme fuse fwo to maleh wi th expeint -36 458.75 X10 g-mt H