The concentration of Mg+2 ions in a sample of coastal seawater is 1.09g/Kg. What is the molarity of Mg+2 in this seawater? (Assume the density of seawater is 1.02g/ml).
Molarity = (weight / molar mass) x (1000 / volume in ml)
Molar mass of Mg = 24.305 gram/moles;
Weight = 1.09g/1kg
Since density = mass/volume
volume of sea water = mass/density
= 1000 gram / 1.02 gram/ml
= 980.39 ml
Molarity = (1.09 / 24.305) x (1000 / 980.39)
= 0.044846 x 1.020
= 0.04574 moles/Liter
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