2&3 only A power lifts 500 lb 6 ft off the ground. how much work has...

Question

Question

2&3 only

Answer 1

Answer #1

1st two answers are right.

1 ft-lb = 1.355 Joules

therefore 3000 ft-lb = 3000 x 1.355 = 4065 J

1 cal = 4.18 Joules

and so Work done in calories will be: 4065/4.18 = 972.5 cal.

Total Energy used up in 11 reps of this weight lift will be : 11 x 4065 J = 44,715 J

if this is done in 1 minute then the Power Output will be:

44,715/60 = 745.25 W approximately 1 Horse Power.

3) Dosage = 0.35mg/kgof body weight

1lb = 0.45kg

so 215lb = 215 x 0.45 = 96.75 kg

therefore the total dose in one administration will be : 0.35 x 96.75 = 33.8625mg

Answer 2

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