Solution :
Given that ,
mean = = 138
standard deviation = = 32
a) P(112 < x < 162) = P[(112 - 138)/32 ) < (x - ) / < (162 - 138) /32 ) ]
= P(-0.81 < z < 0.75)
= P(z < 0.75) - P(z < -0.81)
= 0.7734 - 0.2090
0.5644
The probability that randomly selected value from is population is between 112 and 162 is 0.5644
Given that ,
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