Question

A random variable follows the normal probability distribution with a mean of and a standard deviation of . Complete parts​ (a) through​ (d) below.

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Answer #1

Solution :

Given that ,

mean = \mu = 138

standard deviation = \sigma = 32

a) P(112 < x < 162) = P[(112 - 138)/32 ) < (x - \mu ) /\sigma  < (162 - 138) /32 ) ]

= P(-0.81 < z < 0.75)

= P(z < 0.75) - P(z < -0.81)

= 0.7734 - 0.2090

0.5644

The probability that randomly selected value from is population is between 112 and 162 is 0.5644

Given that ,


answered by: ANURANJAN SARSAM
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