The Major Products are kept
inside Red Box.
Me 1. LiN(iPr)2 (1.05 equiv) THF, -78 to RT 2. Me Me Br 3. (Ph3P)3RhCl (1...
4. Predict the Product: NaBHA MeOH 1. LAH 요 2. H30* Ph3P li Php NaOEt EtOH 1. TBS-CI, imidazole ОН ОН 2. HO TsOH 1. NaOET 2. Br Br 3. NaOET 1. (1.1 equiv) LDA THF, -78°C 2. Br 1. (0.9 equiv) LDA THF, 0°C 2. Br
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liquid ND3 1. Br2, CCl4 2. NaH (3 equiv.), CH3I THF 3. Do, Pd/CaCO quinoline 1. Br2, H2O 2. NaH, THF 3. LiAID4, ether 4. H30+ 1. LiNHo, NH 2. BHa THF 3. H2O2, NaOH 4. NaBH3, EtoD
predict the products
1. Mg (1 еq), Et20 V. -Br 2. (1 eд) «СНО 3. HС, Н20 W. 1. NaBH, MeCОН, 0° С 2. PBrз, THF 3. LIAID4, THF 4. HСI, Н-О ОН х. 1. SOCI2, NEt3, THF 2. 2 eq Li, hexane 3. НСІ, НО СНО т
-NH2 PCC, CH2Cl2 NaBH CN OH 8 Br 1. 3 equiv. 12 4 equiv. NaOH 1. LiAlH4 2. H2O 2. H30* 9 10 2 equiv. (CH3)2NH 1. LiAIH 2. H20 11 12 H2O 1. CH,MgCI 2. H30 13 14
Provide the major product for the following reactions:
b. NaH, THF CH Br 1.1 eq LDA, THF D O NaOD 1. LDA (1.1 eq) 2. CH2CH 3. LDA (1.1 eq, -78 °C) 4. CH 1 equiv. Br2 NaOH, H2O
O Ç(CH3)3 1) CH3CCI, AICI: 2) (CH3)2NH H2, Raney-Ni, heat CO Me 1) PhMgBr (2 equiv.) 2) H2O, H30+
1. (4 pts) Predict the product for the following transformations 1. Ph NH2 (2 equiv) 2. LIAIH, THE 3. H30 Me Me 1. Meo_c xylenes, heat 2. DIBALH, THE 3. H,O* HN CH2Cl2 Me 4 4. (2 pts) Provide the necessary reagents for the following transformation. an
Which reaction sequence would convert 1H-indene to 2-deuterioindane? -D O A. 1. BH3-THF 2. H2O2, OH 3. PBr3 4. Mg(s), Et20 5. D20 B. 1. DCI 2. Mg(s), Et20 3. H2O OC. 1. HCI 2. Nal 3. D20 D. 1. D2, Pd/C 2. Cl2, hv 3. Mg(s), Et20 4. H20 What is the correct order of chemical shifts (from lowest to highest) in the 13C NMR spectrum of methyl benzoate? O A. II<I< III B. III < I< 11 C....
Br 1. 3 equiv. 12 4 equiv. NaOH 1. LiAlH4 2. H2O 2. H30+ 10
hh.) OEt 1. LIAIHJE!,0/-78 °C 2. H,0 1. LIELO 2. Ph.CO 3.H30 Br 1. Mg/THF 2. formaldehyde 3. NHCl(aq) kk.) 2 Na, EtOH, NH CH,BF mm.) SOH 2 Na, EtOH, NH, nn.) NOZ H2SO4(conc) HNO3(conc) NO 00.) 1. SO, H,SO 2. NaOH/KOHA 3. H,0*