Please explain steps: 1) Draw the circuit for the function f (x, y, z) -y +x...
Implement the Boolean function F(w,x,y,z) = Σm(3, 4, 5, 1 1, 12, 13, 14, 15) using a minimum number of NAND gates only. Write the minimal logic expression (no need to draw the circuit).
Given the function below, F(w,x,y,z)= x’z+w’z’+w’y a) draw a logic diagram for an implementation which uses only five two-input NOR gates. b) Implement the function of parts a using only four two-input NAND gates. Draw the logic diagram. USE K-MAP TO SOLVE.
Q2: 1. Proof this Boolean expression. Use Boolean Algebra (X+Y). (Z+W).(X'+Y+W) = Y.Z+X.W+Y.W 2. For this BF F(X,,Z)=((XYZ)(X +Z))(X+Y) • Design the digital circuit Derive the Boolean Function of X, Y, Z. Simplify the Function Derive the truth table before and after simplification. Derive the BF F(X,Y,Z) as Maxterms (POS) and miterms (SOP). Implement the F(X,Y,Z) after simplification using NAND gates only. Implement the F(X,Y,Z) after simplification using OR NOR gates only.
1) Draw the diagram of XOR gate using AND, OR and NOT gates only 2) Draw the diagram of this function (x,y) = (x’y + xy’ + x’y’) using NOT, AND gates only 3) Draw the diagram of this function (x,y,z,w) = (x’ + y’).(z + w) using 2 input NAND gates only Draw the diagram of this function (x,y,z) = xy’z using 2 input NAND gates only.
We are interested in designing a circuit that implements the following three Boolean functions: 3. h(x,y,z)=Σm(1,4,6) f1x,y,z)- > m(1,4,6) y-m35) (x,y, z) Σ m (2,4,6,7) 左 You are supposed to implement the circuit with a decoder constructed with NAND gates (a) [12pt] Start by drawing the block diagram of a NAND-based decoder with three inputs (x,y,z), labelling all the outputs with their corresponding Boolean functions (b) [8pt) Using a new block diagram of the NAND-based decoder, implement the circuit using...
Design a combinational circuit with three inputs, x , y, and z, and three outputs, A, B , and C . When the binary input is 0, 1, 2, or 3, the binary output is one greater than the input. When the binary input is 4, 5, 6, or 7, the binary output is two less than the input. 1) Truth table 2) Logic circuit 3) Boolean function of A using minterms ( use Boolean algebra) 4) Boolean function of...
Implement the function F (x,y,z)= (not x)(not z)+ xy using a. One 4-to-1 multiplexer and any additional inverters. Show your truth-table and justify your choice of select inputs. b. One 2-to-1 multiplexer and the minimal number of gates. Show the truth table used to derive your circuit.
7) Construct the truth table for the function F(X,Y,Z) = Y’Z+ X Z’ 8) Draw the logic circuit for the function F(X,Y,Z) = Y’Z+ X Z’
partb
Problem 2 [15 points] Consider again the function F(x, y, z, w) from problem 1. (a) [5 points) Implement F using one 2-1 MUX and additional gates (show work for all choices for the selection variables) (b) [5 points] Implement F using only 2-to-1 MUXes and no additional gates (this means that NOT gates are not available as well). Explain how dy ny rx 0
CMOS only. For the expression F = AB + AC, draw the corresponding logic circuit using (a) CMOS NAND gates only and (b) CMOS NOR gates only.