Question

The temperature of the Earth's crust increases by about 3.33 degrees C for every 100 m deeper into the Earth you go. Determine the heat transported out of the Earth in one day over the entire surface of the Earth? The thermal conductivity of the Earth's crust is about 0.800 W/(mC). The radius of the Earth is 6.38 times 10^3 km.

Answer 1

rate of heat transfred, dQ/dt = k*A*dT/t

= 0.8*(4*pi*Re^2)*3.33/100

= 0.8*(4*pi*(6.38*10^6)^2)*3.33/100

= 1.3626*10^13 J/s

heat transported out in one day, Q = (dQ/dt)*dt

= 1.3626*10^13*24*60*60

= 1.18*10^18 J <<<<<<<<<-------------------Answer