According to avogadro's law 1 mole of subtance contain 6.022 X 1023 molecule
therefore 6.022 X 1023 molecule of compound NH4Al(SO4)2.12H2O = 1 mole of NH4Al(SO4)2.12H2O
molar mass of NH4Al(SO4)2.12H2O = 453.3102 g/mol
1 mole of NH4Al(SO4)2.12H2O = 453.3102 gm
therefore mass of 6.022 X 1023 molecule of compound NH4Al(SO4)2.12H2O = 453.3102 gm
what is the mass (grams) of 6.022 x 1023 potassium atoms? - How many sodium atoms are there in 5.000 moles? How many sodium atoms are there in 100 narams of sodium?
QUESTION 26 What is the mass, in grams, of one arsenic atom (NA- 6.022 x 1023 mol-1? O 5.48 x 10-23g O 33.0 g O 74.9 g O 1.24 x 10-22 g O 804 x 1021 g
What is Charge of the Al in KAl(SO4)2. 12H2O ? Wouldn't it be +3? If not, why?
3. What is the mass in grams of 6.022 x 1023 molecules of CO2? A. 22 g B. 44 g C. 668 D. 28 g
1. One mole of sodium atoms contains: a) 23 atoms b) 6.022 x 1023 grams c) 6.022 x 1023 atoms d) 60.22 x 1023 atoms
Recycling Al experiment Mass of Al : 0.49g Mass of KAl(SO4)2 12H2O synthesized: 2.86g 1. Assuming you started with pure aluminium scrap, calculate the theoretical mass of the precipitate, alum. Include a balanced net ionic equation for the formation of the product from Al3+. 2. Calculate your percent yield. 3. If you had a large number amount of impurities in the scrap aluminium, what would be the impact in the percent yield calculation? explain. 4. In this experiment volume of...
How much energy is associated with a mole (6.022 x 1023) of photons with a frequency of 4.30 x 1014 s-1 ( Answer in kJ to 3 sig figs)
balance the chemical equation Al2(SO4)3(aq)+K2SO4(aq)+24H2O(l)—> 2KAl(SO4)2•12H2O(s)
2Al(s)+2KOH(aq)+4H2SO4+22H2O(l)→2KAl(SO4)2⦁12H2O(s)+3H2(g) What is the limiting reactant, theoretical and percent yield of this equation? 1.03 grams of Al foil 35.10 grams of KOH 15 grams of Sulfuric acid 20 grams of water the mass of the product is 24.88 grams
What is the molar mass of glucose, CH1205? What is the mass of 4.73 x 1023 atoms of silver, Ag?