Calculate the pH of a 0.340 M NaO2CCO2H solution. pK1 = 1.250 and pK2 = 4.266
Calculate the pH of a 0.340 M NaO2CCO2H solution. pK1 = 1.250 and pK2 = 4.266
Calculate the pH of a 0.03 M NaO2CCO2H solution. pK1 = 1.250 and pK2 = 4.266. THE ANSWER IS NOT 2.89 IT IS 2.76 Please show your work. Thanks!
Calculate the net charge of arginine (pK1=2.17, pK2=9.04, pK3=12.48) at pH 6.0. In order to calculate the net charge you must first calculate the percent “charged” for each ionizable functional group in the chemical structure of arginine. Use four significant digits in your calculation of the net charge.
2) Calculate the pH of 0.08 M Na2HPO4 H3PO4 S H+ + H2 PO4 pK1 = 2.1 H2PO4 5 H+ + HPO42- pK2 = 7.2 HPO42- 5 H+ PO43- pK3 = 12.3
What is the pI of glutamate? pK1= 2.2 pK2=3.5 pKr=8.5 Rule: pH > pKa deprotonated, pH < pKa protonated
Given that pK1 = 3.0 and pK2 = 8.0 for an amino acid X. Total concentration of amino acid X in solution is 10 mM. Calculate the concentrations of protonated form (P), dipolar form (Z) and de-protonated form (D) of amino acid X at pH 2, and 10.
Calculate the [H_3O^+] and pH of the following polyprotic acid solution 0.340 M H_2C_2O_4. Calculate the pH of this solution
The amino acid Prolinehas a pk1 of 1.99, pk2 of 10.60. The amino acid Serine has pk1 of 2.21 and a of pk2 of 9.15. If these two amino acids bind together by peptide bond creating the peptide sequence Pro-Ser . What will be the overall charge of this peptide at the physiological pH of 7?
A 125.0-mL aliquot of 0.121 M diprotic acid H2A (pK1 = 4.01, pK2 = 8.02) was titrated with 1.21 M NaOH. Find the pH at the following volumes of base added: Vb = 12.50, 13.50, 18.75, 24.00, 25.00, and 29.00 mL. (Assume Kw = 1.01 ✕ 10−14.)
A 1000 mL aliquot of .1 M diprotic acid H2A (pK1=4; pK2=8) was titrated with 1 M NaOH. find pH values at Vb: 0, 3, 8, 10, 13, 19, 20, 22.
One liter of an aqueous solution contains 0.060 M valine at its isoelectric point. Given: pK1 = 2.3; pK2 = 9.6. If 0.020 moles of strong acid are added (at constant volume), the new pH will be