A 125.0-mL aliquot of 0.121 M diprotic acid H2A (pK1 = 4.01, pK2 = 8.02) was titrated with 1.21 M NaOH. Find the pH at the following volumes of base added: Vb = 12.50, 13.50, 18.75, 24.00, 25.00, and 29.00 mL. (Assume Kw = 1.01 ✕ 10−14.)
A 125.0-mL aliquot of 0.121 M diprotic acid H2A (pK1 = 4.01, pK2 = 8.02) was...
A 100.0 mL aliquot of 0.100M diprotic acid H2A(pK1 = 4.00; pK2 = 8.00) was titrated with 1.00 M NaOH. Find the pH values at the following volumes of base added, Vb; Vb= 0 mL, PH= Vb= 2 mL, PH= Vb= 8 mL, PH= Vb= 10 mL, PH= Vb= 12 mL, PH= Vb= 18 mL, PH= Vb= 20 mL, PH= Vb= 22 mL, PH=
A 1000 mL aliquot of .1 M diprotic acid H2A (pK1=4; pK2=8) was titrated with 1 M NaOH. find pH values at Vb: 0, 3, 8, 10, 13, 19, 20, 22.
A 100.0-mL aliquot of 0.100 M diprotic acid H2A (PK1 = 4.00, PKa2 = 8.00) was titrated with 1.00 M NaOH. Find the pH at the following volumes of base added. a) 1 ml, b) 11 mL, c) 20 mL and d) 22 mL.
A 100.0 mL aliquot of 0.100 M monoprotic acid H2A (pK1 = 4.00) was titrated with 1.00 M NaOH. Find the pH at the following volumes of base added: Vb = 0, 5, 9, 10 and 11 mL. Sketch the titration curve.
A 100.0m aliquot of 0.100 M diprotic acid H₂A (pk, = 4.00; ph2 = 8.00) was titrated with 1.00M NaOH. Find the pH at the following volumes of base added, Vb: 0mL, 2mL, 8mL, 10mL, 12 mL, 18mL, 20mL, 22mL,
6. A student titrated 50.0 mL of the 0.10 M unknown diprotic H2A with 0. 10 M NAOH. After 25.0 mL of NaOH was added, the pH of the resulting solution was 6.70. After 50.0 mL of NaOH was added, the pH of the solution was 8.00. What are the values of Ka1 and Ka2? 6. A student titrated 50.0 mL of the 0.10 M unknown diprotic H2A with 0. 10 M NAOH. After 25.0 mL of NaOH was added,...
A student titrated a 25.00-mL sample of a solution containing an unknown weak, diprotic acid (H2A) with NaOH. If the titration required 17.73 mL of 0.1036 M NaOH to completely neutralize the acid, calculate the concentration (in M) of the weak acid in the sample. (a) 9.184 x 10‒4 M (b) 3.674 x 10‒2 M (c) 7.304 x 10‒2 M (d) 7.347 x 10‒2 M (e) 1.469 x 10‒1 M
A 120.0-mL aliquot of 0.114 M weak base B (pKb = 4.58) was titrated with 1.14 M HClO4. Find the pH at the following volumes of acid added: Va = 0.00, 1.30, 6.00, 11.00, 11.90, 12.00, 12.10, and 17.00 mL. (Assume Kw = 1.01 ✕ 10−14.)
Acid/Base titrations 10. 25.0 mL of 0.100 M H2A (a weak diprotic acid) is titrated with 0.200 M NaOH. What is the pH of the solution when 0.00 mL, 10.0 mL, 12.5 mL, 20.0 mL, 25.0 mL, and 40.0 mL E.S RaWeMA 5.83 x 10 8) have been added? (Ka1= 2.46 x 10, Ka2 ANSWER: 0 mL = 2.315, 10.0 mL= 4.211 (or 4.213), 12.5 mL = 5.422, 20.0 mL 7.410, 25.0 mL = 9.966, 40.0 mL = 12.664 11....
A 20.00 ml aliquot of a 1.00 M solution of a weak acid (Ka = 1.50E-04 at 25ºC) is titrated with 0.500 M NaOH. Determine the pH at the following volumes of NaOH. Volume NaOH = 30.00mL , pH? Volume NaOH = 40.00mL , pH? Volume NaOH = 47.50mL , pH?