Question

N 200 mm c N 300 mm] inlied force N = 5 kN, determine the torqu

a. If the applied force N=5kN, determine the torque at cross section C in N.m
b. The pipe shown has a inner diameter of 50 mm and an outer diameter of 71mm. if its tightened against the support at A using a torque wrench at B by applying a force N =102N instead of 5kN, determine theax shear stress in kPa developed In the material at the cross section C when the forces shown in the figure below are applied to the wrench.

Answer 1

Soll- N=5kw С Torque at'c' 200mm k 300mm {Myco 5x200) + 5(300)_720 T 4 ska Sko T= 2500 komm 200 * 300 T = 2.5 kNm kans Dinner diameter d; = 50mm 25mm outes diameter do - 71 mm Hos 35.5 mm N=102n

Polar Moment of inertia Da ET RY 4 17 CRYRE 1((0.0385)"Coo2sy)] J: 1.8811x10 Y Shear stress at a Torque T = (102x0-2) + (102x0-3) T-51 nm DO vo 0.0355 35.5mm - = 2 To=TO = 51 x 0.0355 188118766 J Po= 0.962 MPa lice T - Kanswer Shear Steress at C outes 0.962 mpa Shear stress at C inner Section C; 20.025 T=51nm Tc; - TC; 51 0.025 20.687mpa 1.8811 X 106 ? 70.677 MPa f Answer 1 J