Question

914885136 X Content * Microsoft Word - phys2x + x E C * Microsoft Word - phys2 x Download - ShowBox X W Example Lab 253 - Skys webcourses.niu.edu/ultra/courses/_3032501/cl/outline -78.33 points KatzPSEf1 3.WA.04.002. Tutorial. 0/6 Submissions Used 12. B My Notes Ask Your Teacher A spaceship is traveling through deep space towards a space station and needs to make a course correction to go around a nebula. The captain orders the ship to travel 1.3 x 10 kilometers, then turn 70° and travel an additional 2.3 x 106 kilometers to reach the space station. If the captain had not ordered a course correction, what would have been the magnitude and direction of the path of the spaceship if it had traveled through the nebula? space station nebula magnitude direction spaceship km • counterclockwise from the +x axis Need Help? Read It Submit Answer W3 0 -9:10

Answer 1

As shown from the figure, resolve location of the spaceship into rectangular components along the xy plane R, ABcos(70 - 1.3x10 Km+2.3x10 Km) cos (70) COs -2.0866x100 Km R, Bsin70 -(2.3x10 Km)sin (70") 2.16129x10 Km Magnitude of resultant distance travelled by the spaceship is R R2+R,2 (2.0866x10 Km) +(2.16129x10 Km) X - =3.004x10 Km 3.0x10 Km Direction of resultant distance travelled by the spaceship is, tan 2.16129 x10 Km 2.0866 x10 Km -1 Ctan 46" CCWx axis