Question

Initials: 10 Who next to the question number *** d. [20, 40, 60, 80, 100) 27. What is the output? new_list - (223, 645, 500, 10, 22) new_list.sort() for i in new list: ind - new_list.index (1) if ind > 0: new_list(ind-11 + 1 print(new_list) a. [868, 1145, 510, 32,22] b. [32, 245, 723, 1145, 645) c. [22, 32, 510, 1145) d. [10, 22, 223, 500, 645) - 28. Complete the following code to print the average of the list. new_list = [0, 1, 2, 3, 4] ## missing code ## print("The average is {)" .format(avg) ) a. avg = sum(new_list)/( max(new_list) - min(new_list) b. avg = sum(new_list( max(new_list) + min(new_list)) c. avg = sum(new_list)/max(new_list) d. avg = sum(new_listlen(new_list) 29. What is the length of the dictionary my_dict = ['Country': 'India', 'State': {'City':'Delhi', 'Temperature':40})? a. 4 b. C. 3 2 d. 5 30. Select the option to get the value of temperature from the dictionary my dict - ('Country':'India', 'State': {'City':'Delhi', 'Temperature':40}). a. my_dict[1][1] b. my_dict['State']['Temperature'] C. my dict.State. Temperature d. My_dict [4]

Answer 1

27.
   b.
       [32, 245, 723, 1145, 645]

   Explanation:
       Pass #1:   [10, 22, 223, 500, 645]
       Pass #1:   [32, 22, 223, 500, 645]
       Pass #1:   [32, 245, 223, 500, 645]
       Pass #1:   [32, 245, 723, 500, 645]
       Pass #1:   [32, 245, 723, 1145, 645]

28.
   d.   avg = sum(new_list)/len(new_list)

   Explanation:
       The avg can be calculated by (sum of outcomes/ no. of outcomes)

29.
   c.   2

   Explanation:
       The my_dict contains only two objects one is of type string and second is another object of type dictionary.

30.
   b.   my_dict['State']['Temperature']

   Explanation:
       [] is used to access the values of the dictionaries, by passing the appropriate key values.