Question

A chemistry student weighs out 0.0873 g of formic acid (HCHO) into a 250. ml. volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1500 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Be sure your answer has the correct number of significant digits. ml X s ?

Answer 1

Molecular weight of formie acid (HCOOH) = ((1+2) + (12x1) + (1682) amor = 46 g/mol acid = 0.0873 met 0.0873 8 y formic so in 250 ml solution contain 0.0873 mol af HCOOH 46 & in 1000 ml solution contain (0.0873 x1000) mol af HCOOH 46 x 250x1000) mol = 7.59 810 3 mol of HCOOH . Molar concentration y this solution - 7.59x10 3 M Now, we know, visi = V₂ S2 M here, V = volume & Hero = 250 ml si concentration of HeroH = 7.59 x 10 V₂ = volume of NagH = ? S2 = concentration of Math = 0.1500 m so vs, = V₂ S2 or, V = Visi S2 250 × 7.598 10 3 0.1500 ML = 12.65 ml ~ 12.6 ml in 3 siginificant digit] Heme, 12.6 ml of MacH required to titrate given solution.