Question

Answer: 24 ei 0t1 Problem 7.8. A man hits a ball of radius R and mass m cal rod of length L and mass M (Fig. P.7.8). Before thei ylindri had an initial velocity vo e2 and angular velocity ao e3 as figure. The rod, on the other hand, wa oint A with angular velocity- o e3. The distance between the poin of impact and point A is denoted as d. Assume the force of impulse be perpendicular to the contact area. Determine the angular velocity o of the rod and velocity of the center of mass v of the ball immediat after the impact. Use the following parameter values in your com tations: M 10 kg, L 1 m, d -0.8 m, slo 5 rad/s, m 5 kg, R1 m, vo 10 m/s, and the coefficient of restitution e 0.8. impact the ball s rotating around the stationary u-

0 0
Add a comment Improve this question Transcribed image text
Answer #1

2m2+mv 5 3 3 a) E0-52556 23nodlisot

Add a comment
Know the answer?
Add Answer to:
Answer: 24 ei 0t1 Problem 7.8. A man hits a ball of radius R and mass...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A ball of mass M = 1.40 kg and radius r = 4.70 cm is attached...

    A ball of mass M = 1.40 kg and radius r = 4.70 cm is attached to one end of a thin, cylindrical rod of length L = 12.0 cm and mass m = 0.880 kg. The ball and rod, initially at rest in a vertical position and free to rotate around the axis shown in the figure below, are nudged into motion. M m (a) What is the rotational kinetic energy of the system when the ball and rod...

  • 3. As shown above, the hammer in black hits the ball of mass 'm' at the...

    3. As shown above, the hammer in black hits the ball of mass 'm' at the end of a metal rod of diameter 'd'. This imparts an instantaneous velocity of Vo to the mass. Treating the rod as a massless spring of spring constant K such that %,where E is the modulus of elasticity of the rod material, A is the cross sectional area of the rod, and L is the length of the rod, derive an expression for the...

  • PROBLEM 17.113 The slender rod AB of length L = 1 m forms an angle B...

    PROBLEM 17.113 The slender rod AB of length L = 1 m forms an angle B = 30° with the vertical as it strikes the frictionless surface shown with a vertical velocity 7 = 2 m/s and no angular velocity. Knowing that the coefficient of restitution between the rod and the ground is e = 0.8, determine the angular velocity of the rod immediately after the impact.

  • please do not just copy solution manual.. B PROBLEM 17.113 The slender rod AB of length...

    please do not just copy solution manual.. B PROBLEM 17.113 The slender rod AB of length L = 1 m forms an angle B = 30° with the vertical as it strikes the frictionless surface shown with a vertical velocity 7 = 2 m/s and no angular velocity. Knowing that the coefficient of restitution between the rod and the ground is e = 0.8, determine the angular velocity of the rod immediately after the impact

  • 2. (40 points) A soccer ball tester consists of a 15-kg slender rod AB with a 1.1-kg sim- ulated foot located at A and a torsional spring located at pin B. The torsional spring has a spring const...

    2. (40 points) A soccer ball tester consists of a 15-kg slender rod AB with a 1.1-kg sim- ulated foot located at A and a torsional spring located at pin B. The torsional spring has a spring constant of k 910 N.m/rad and is unstretched when AB is its lowest position. Fig. 2 depicts the simulation. The length of AB is 0.9 m, and you can assume that the foot ban be modcled as a particle, Knowing that the velocity...

  • The ball A of mass 8 kg is attached to the light rod of length /...

    The ball A of mass 8 kg is attached to the light rod of length / = 0.77 m. The mass of the carriage alone is 204 kg, and it moves with an acceleration ao as shown. If = 2.5 rad/s when ? = 90°, find the kinetic energy T of the system if the carriage has a velocity of 1.59 m/s (a) in the direction of ao and (b) in the direction opposite to ao. Treat the ball as...

  • a. The mass of a golf ball is .046 kg; the mass of a club head...

    a. The mass of a golf ball is .046 kg; the mass of a club head is .28 kg; and, the velocity of the club head is 55 m/s before it impacts the ball. If the coefficient of restitution of the ball is .82, how fast is the ball moving after impact? (1pt)          Use this formula for part a.: v1 = ((CoR + 1)m2u2 + u1(m1 – CoRm2)) / m1 + m2                   Where     v = velocity after...

  • A solid disk of mass m = 9.2 kg and radius R = 0.2 m is...

    A solid disk of mass m = 9.2 kg and radius R = 0.2 m is rotating with a constant angular velocity of w = 38 rad/s. A thin rectangular rod with mass m2 = 3.7 kg and length L = 2R = 0.4 m begins at rest above the disk and is dropped on the disk where it begins to spin with the disk. 1) What is the initial angular momentum of the rod and disk system? kg-m2/s Submit...

  • 1. A ball is revolving horizontally in a circle of radius 1.8 m, and is held...

    1. A ball is revolving horizontally in a circle of radius 1.8 m, and is held by a rigid massless rod. The mass of the ball is 0.1 kg. The ball has a constant linear speed of 27 m/s. What is the angular velocity of the orbit in rad/s? a. 15 b. 2.3 c. 0.6 d. 5.4 e. 0.1

  • D PROBLEM 17.127 Member ABC has a mass of 2.4 kg and is attached to a...

    D PROBLEM 17.127 Member ABC has a mass of 2.4 kg and is attached to a pin support at B. An 800-g sphere D strikes the end of member ABC with a vertical velocity vi of 3 m/s. Knowing that L = 750 mm and that the coefficient of restitution between the sphere and member ABC is 0.5, determine immediately after the impact (a) the angular velocity of member ABC, (b) the velocity of the sphere

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT