delta H = BE(reactant) - BE(product)
-137 = BE(C=C) + 4*BE(C-H) + BE(H-H) - BE(C-C) - 6*BE(C-H)
-137 = BE(C=C) + BE(H-H) - BE(C-C) - 2*BE(C-H)
-137 = 614 + 436 - 348 - 2*BE(C-H)
2*BE(C-H) = 839
BE(C-H) = 420 KJ
Answer: A
Given the following bond energies and the heat of reaction for the process below, estimate the...
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