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1. A thin plate walls are exposed to constant temperatures T1 and T2 as shown in the figure. If the temperature distribution

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T dr-o - integroting above equation integrating again, we have T= araç conditions, Applying boundary X=-, TOT x=1, T=Tz Ti=-C1.2) Xeo Trze = [C60-100) X0 + (93460)] Tres - Soc ! at mid-point temperature = 80°C = Soºc 1.3) heat flux is given by q=-konthe temperature distribution expression,mid point temperature and the the thermal conductivity has been answered as shown

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