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Question 2 (20 marks): A 1 kg ball A is traveling horizontally at 20 m/s when it strikes a 10 kg block B that is at rest. If

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mo-lokg mA = 1kg UA = 20m/s UB=0 After collesion 1. momentum conserved Maua+MBUR = MAVA + more 9x20 + loxo = 1X VAT lovu 7 VAPart-2 Ng=3%ms W = 0 from newtons equation of mosion V = wt at from FBD of Block & x = Mafn 7 x = 0.4x10x10 auon t = -ma -Mainly concepts involved in this question are:

1. Conservation of momentum in collision

2. Conservation of Energy in Collision

3. Newton's equations of motion

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