Question

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range: 415 421 422 422 425 429 431 435 436 439 445 447 450 453 459 463 464 (a) Construct a bowplot of the data. 124 W 4.pdf physics 2 la OBS 420 440 450 420 480 440 460 Eclipse 420 420 430 440 460 450 440 450 physics 4b ohr ands pee heat combined resistors Comment on any interesting features. (Select all that apply) The data is strongly skewed. There is one outler The data appears to be centered near 439 The data appears to be centered near 429. There is little or no skew There are no outliers. X Sb opacitance charged energ (b) Is it plausible that the given sample observations were selected from a normal distribution? O Yes NO se combined Capacitor (c) Calculate a two-sided 95% confidence interval for true average degree of polymerization. (Round your answers to two decimal places.) 400.49 X 44621 Does the interval suggest that

Answer 1

Boxplot :

15 235 36 55 الذات 15 وه 25 35 5 55 f

C is correct graph.

The correct option are :

There is little or no skew

There are no outliers.

b) Yes

c)

The 1001f-a)% CI - x I tant x=438.588 s=15.5686 n = 17 to.095;46 = 2.120 - 438.588 € 2.100 x 15.5686 VIF = 1430.5830, 4 46.5930) Auz (430.58, 44 6:59

Note that the average is not centered at 439 since median is at 436.

There are no outliers present since Q1-1.5IQR and Q3+1.5IQR values are much lower and much higher than the min and max values.

423.5-(1.5*28)=381.5

451.5+(1.5*28)=493.5

IQR=Q3-Q1=28