Question

Please solve the solution step by step. It skips steps and confuses me.

Answer 1

"(a) We have w = 2 pi f = 2 pi (400) rads = 80 D pi rads^-1 = 2513.3 rads^-1 Applying KVL across loop 1 -V_s + V_c + V_R = 0 . i.e V_s = i[z_c + z_R] where z is impedance . z = z_c + z_R z_c = 1/ partial wC z_R = R Rightarrow i = V_s/ 1/ partial wc + R 1/wc = 1/2513.3 times 40 mu f = 9.9472 Rightarrow z = 15-j9.9472 = 17.9985L i = 2.4/ 17.9985 < -33.5 = 1.33 < 33.5 V_c = i z_c = (1.33 < 33.5) times (-9.9472j) = 13.3 < -56.5 from V_s = 24 < 0, V_c = 13.3 < -56.5 V_R = 20 < 33.5 Current is leading the voltage Resistance Voltage(V_R) is in the direction of current V_c logs i by 90 [Capacitor] V_R = 20 < 33.3 Rightarrow