Question

Н ОН -H HO HOS HOHT OH glucose Water will be soluble with glucose due available H bonding on the glucose molecule. 4. Outline a procedure for separating anthracene and 4-chloroaniline (shown below) using extraction and possibly acid/base chemistry. NH2 CI anthracene 4-chloroaniline 3 452 Words English (United States) Focus MacBook Ai :o: :0 90f F1 F2

Answer 1

4. As we know that anthracene is a nonpolar aromatic hydrocarbon, so it will be inert in acids and bases which requires a polar medium.

Now, in case of 4-chloroaniline, which is obviously basic in nature due to its amine group, will react with dilute acids to give soluble salts.

Now, if we are given a mixture of the above two, there are practically TWO kinds of the separation method. One is simply on the basis of solubility in a polar medium. The other is using the basic character of the latter i.e just take the mixture and add any dilute acid (say, dilute HCl), and one will observe that the 4-chloroaniline getting dissolved by the formation of a chloride salt and the anthracene remaining insoluble withing the mixture. Then filter out the soluble part( which contain 4-chloroaniline) and add some dilute NaOH and the excess acid is neutralized and 4-chloroaniline is separated out from the mixture finally.

Mixture taken in a Beaker + 1 + EDL insoluble soluble salt 1 Filtered t the soluble #e, Fovito ED I nach E thel