Question

$TpH50TY2bD%2Fwebassign_magnetism_torque.$

Use these values: the width of the loop is 21.0 cm;
the length of the loop is 80.0 cm;
the current I = 6.00 amps;
the field B = 6.00 T.

A) Calculate the net torque on the loop when the loop is in the orientation shown above.
_______ N m

B)Calculate the net torque on the loop when the loop, as seen from the side view, has rotated through an angle of 38.0 degrees.
_______ N m

Answer 1

Find the area normal and use equation for torque on a current loop to find the required solution as shown below.

area normal is, А = kxЬ - (0.8m) x (6-21m) = 0.168m2 out of page I= u Bsine = IABsino Lo angle between area normal and field, here o=90° = (6A0.168m2)61) singar = 16.048 N.m ÅR I inital → 36 direction B) Now 0 = 90 - 38° - 52° So, T = u Bsino = IA Bsino = (CA)0·268m261) sin 52° = (4.77 Nm

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