Question

You have stock solutions of 40% acrylamide and 2% bis-acrylamide in H2O (both w/v). You need...

You have stock solutions of 40% acrylamide and 2% bis-acrylamide in H2O (both w/v). You need to prepare 100 mL of solution with maximal concentration containing 37.5 : 1 acrylamide - bis-acrylamide ratio.

a) How many mL of each stock solution do you have to take for preparation?

b) How many mL of the prepared solution you have to take in order to prepare 10 mL of 12% (by acrylamide) gel for PAGE?

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Answer #1

A (a/a+b).* 100

(37.5/38.5) * 100 = 97 ml Remaining 2.5 is bis acrylamide

97ml Acrylamide and 2.5ml bis-acrylamide

B. 40% * x = 12% * 10ml

X= 3ml

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