What is the pH of a buffer that is 0.379 M HF and 0.374 M LiF? The Ka for HF is 3.5 x 10-4. If the ΔH = 109 kJ/mol and ΔS = 100 J/K mol, at what temperature does this reaction become spontaneous?
therefore the reaction becomes spontaneous when T = 1090K ( 817ºC)
Calculate the pH of a buffer that is 0.040 M HF and 0.020 M LIF. The Ka for HF is 3.5 x 10-4.
Calculate the pH of a buffer that is 0.040 M HF and 0.020M LiF. The Ka for HF is 3.5 x 104
Calculate the pH of a buffer that is 0.020 M HF and 0.040 M LiF. The K a for HF is 3.5 × 10 -4. 2.76 2.06 3.46 4.86 3.76
2 A buffer solution is 0.408 M in HF and 0.379 M in KF. If Ka for HF is 7.2x10 4, what is the pH of this buffer solution?
A 1.00 L buffer solution is 0.250 M in HF and 0.250 M in LiF. Calculate the pH of the solution after the addition of 0.20 moles of solid LiOH. Assume no volume change upon the addition of base. The K a for HF is 3.5 × 10 -4. 3.63 3.46 4.24 2.85 4.41
Question 1 -- / 1 Calculate the pH of a buffer that is 0.058 mol L-1 HF and 0.058 mol L-1 LiF. The ka for HF is 3.5 x 10-4. 9.31 2 10.54 3 3.46 4 4.69 © 2.86
Determine the pH of 1.33 M LiF. For HF, Ka is 6.8 x 10^-4.
1a. ) Complete the table with signs and general values for K (ie: K<1 or K>1) Always spontaneous Always nonspontaneous Spontaneous at high temperatures ΔG ΔH ΔS K 2. Calculate the boiling point (in K) for the following: X2 (l) --) X2 (g) ΔH = +35 kJ ΔS = + 215 J/K (HINT: what does ΔG equal when a reaction switches from spontaneous to nonspontaneous?) 1b. ) Trick question (refer to the table in #1): at what temperature does the...
What is the pH of a buffer solution containing 0.13 M HF and 5.0×10−2 M NaF? What is the pH of a buffer solution containing 1.0×10−2 M HF and 0.16 M NaF? Using the table given below for Ka values, compare the pH of an HF buffer that contains 0.13 MHF and 5.0x10-2 M NaF with another HF buffer that contains 1.0x10-2 MHF and 0.16 M NaF. Ka and K b values for selected weak acids and bases HF Acid...
What is the pH of a buffer solution that is 0.400 M in HF and 0.790 M in NaF? Ka of HF = 7.2 ✕ 10-4.