please provide explaination because i have hard time understand this problem
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please provide explaination because i have hard time understand this problem The same object (height =...
Diverging & Converging LENS
The same object (height = y) is placed at several different
distances s to the left of the same lens (focal length = f). For
each case, draw the 3 principal rays to locate the image. Then use
the “thin lens” equations to calculate:
• the image height y' (in terms of y)
• whether the image is real or virtual
• the image distance from the lens s' (in terms of s and f)
•...
All the details I have been
given. NO more info provided!!!
For each of the following diagrams: Draw the 3 principal rays to locate the image. Then, using your drawing Give the image height in centimeters Give the image distance from the lens in centimeters First: use a ruler to determine the focal length in centimeters. You can use this information to help you estimate the size and location of your images f cm 1) S=2f It this image real...
*I know the answer, please provide visual representation of lens diagrams* A converging lens has a focal length of 10.0 cm. Locate the images for object distances of (a) 20.0 cm, (b) 10.0 cm and (c) 5.00 cm, if exist. For each case, state whether the image is real or virtual, upright or inverted, and find the magnification
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An object of height 9.00 en is placed 33.0 cm to the left of a converging lens with a focal length of 12.0 cm. Determine the image location in em, the magnification, and the Image height in cm HINT (a) the image location in cm cm (b) the magnification (c) the image height in cm Om (d) is the image real or virtual Oreal (el is the image pright or inverted? inverted An object...
ASAP please.
3. An object is placed at 10 cm from a thin converging lens of focal length f. Its image is formed 30 cm from the lens on the same side as the object. (20 points) (a) What is the focal length? (4 points) (b) What are the magnification of the image, the orientation of the image (upright/inveredy (2+2 (c what kind ofimage is formed (reduced/magnified, real/virtual, and uprigh?1nvertedy? (2+2 (d) If the lens is replaced by a thin...
An object of height 3.6 cm is placed at 24 cm in front of a diverging lens of focal length, f = -18 cm. Behind the diverging lens, there is a converging lens of focal length, f = 18 cm. The distance between the lenses is 5 cm. In the next few steps, you will find the location and size of the final image. Where is the intermediate image formed by the first diverging lens? Image distance from first lens...
Could you please show all of the steps taken in solving the
problem and explain the process fully, using sentences/phrases (if
possible) to understand why those steps were taken and
why you got that answer.
Also could you please draw a diagram with any applicable
variables/values to help visualize the problem better.
Thank you in advance for all the help!
A 1.20-cm-tall object is 50.0 cm to the left of a diverging lens (lens 1) of focal length of magnitude...
An object of height 3.6 cm is placed at 24 cm in front of a diverging lens of focal length, f = -18 cm. Behind the diverging lens, there is a converging lens of focal length, f = 18 cm. The distance between the lenses is 5 cm. In the next few steps, you will find the location and size of the final image. Where is the intermediate image formed by the first diverging lens? Image distance from first lens...
2. A thin converging lens has a focal length of 10.0 cm. An object is placed 30.0 cm from this lens. Use a sheet of the graph paper provided at the back of this manual to draw a ray diagram that shows the image formed by this lens. Use any two of the three principal (or special) rays and an appropriate scale. Hint: you could let 1 cm on your ray diagram represent 5 cm of the actual measurements:this scale...
Object O stands on the central axis of a thin, symmetric lens. The table refers to the object distance p, the focal distance f, the image distance i and the magnification m. Fill in the missing information, including signs. p (cm) f(cm) i (cm) m +11 +0.40 Describe the lens and image. (Select all that apply.) converging lens diverging lens real image virtual image upright image inverted image image on same side of lens as o image on opposite side...