Question

Problem No. 6.4 110px + I vs = 5.0 V; R = 30.0622; R2 = 12.00; R3 = 48.0kA; R4 = 90.0k2 ; Rs = 32.0 kn Find Vo in the given circuit if the op amp is ideal.

Answer 1

Problem 6.4 Consider the circuit Ra=90kan I [8= 5v / R3 = 48 km2 o} Rg= 32 kr The given opamp is in negative feedback topology, so virtual Short will be there. That is v=vt.

Note :- Virtual Short is a concept which occur in negative feedback topology It states that under negative feedback Configuration, the voltage difference between the inverting and non-inverting input is zero. That vt_v=0 |vt=v-) Now, vt = Vg x R3 + = Vg x R3 (By voltag Bab voltage division R2 + R3 Rule) vt = 5x4K = 4V 12k+48% =

Since ut av we have v-=40 Now, Applyng kel at inverting (v-) terminal Ř VEVO Putting values of v-, R., RA RA 4 + 4 30k 90K – Vo =0. 90k

4x90k+4x30k gok 30kXqOK 480K = Vo 27ook? 9K .. Vo = (480x90) K² 27ook? Vo=16v Note: No Current flowers to the input of the opamp- Since opamp input impedences are very high (200)

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