Change in the temperature = ∆T = 150 - 0 = 150°C
Heat energy given = heat capacity × change in temperature = 3200
So heat capacity = 32000/∆T = 32000/150 = 213.3 J/°C
Heat capacity in nearest whole number = 213 J /°C
Do rate if you understand
LILY FEEDBACK Content attribution Solve heat capacity problems Question David is cooking a brisket and needs...
- 17 days 4/13 Content attribution FEEDBACK QUESTION 5 . 1 POINT If 1.09 g of glucose are burned in a bomb calorimeter, the temperature of the 900. g of water in the calorimeter increases from 15.50 °C to 19.30 °C. If the heat capacity of the calorimeter is 680..what is the value of g for the combustion of the glucose sample? Use water = 4.184 Provide your answer below: FEEDBACK Content attribution QUESTION 6.1 POINT A process that absorbs...