Question

please do 2 and 3

-.-.-.-.-.-.-.-.- 2. Design an inverting amplifier with a gain of -100 at 100Hz. a. Increase the amplitude of the input signal until you observe clipping. Continue increasing the amplitude and observe the results. b. Briefly explain and comment your results. 3. For the same amplifier as in previous exercise number 2: a. Increase the frequency of the input signal until you observe the slew rate characteristic associated with the Op Amp. b. Try different amplitudes C. Briefly explain and comment your results. 4. For the same amplifier as in previous exercise number 2: a. Reduce the value of Rz until the Op Amp will be current limited. b. Change the amplitude of the input signal. c. Briefly explain and comment your results.

Answer 1

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Inveeting amplifies:- B AAA Vin Vout Ideal. - or Vout Vin = ? Since it is virtual case .. Vp tracks VN Ri Rz out = - R 2 closed loop gain openloop gain in Infinity for ex'- Vinov vpvp ou tracks ov. If up traks av. 2v tracks av the closed loop gain is - 1000 of 100hz frequency. Now Vin=-B2 = -100 ut take Rear, R =R 2 R₂ =1000, . R₂ = 1000 Ri=R it let take R =R= 10kr ..R2 = 1000KR R₂ Ri

Vine PK-PK) (Vin LPK-pk ) + R2) If we inecas the input (PK-Pk) amplitude then we obseve. clipping in the output signal. Vout = AC Vp-VN) Aco-VN) VN-Vin VN-vout o Ri R2 UN_Vin tvN vout = 0 R RR RR Vouts al m inimo met] - AR2 - AR2 Wout =-| Ritka , Vin RICHA) + R₂ ARI 1+ It At RitR2 Vout It - AR2 Vin AO RR2 = -R2 1/A.RI ReRe H gain enor

E = 1+ R2 trov + 105V sclipped 100 clipped. 6 of input ult) ut Vo D'ot Vout dvout- = vwu at Imax @at=0 slowrate = dvout = V. Wu. de Imaxeat to The initial slope of this exponentially rising function is Vtimes of wpe. Therefore as long as is sufficiently small so that v. We uss than or equal to slew rate of the op-amp, the output will not slew. Wp = 2 x Slowiate CSR) = V.(2Txf) off increase slewrate reduces increases If slew rate reduces vincular reduces. hele slew rate is proportional to vaf.

96 S-R = 1664 VX2T1xf =s. R f=10043 V OK 2 TT X100 f = 100k Dolj - 1592.3561 V- = 1.5923V 10x27T XIOUX103 f = 100 MHz = 1.5.9x103v. 10X2T X 100 X 106 If frequency changes the slew rate cuts as No5 to 106 7 - 20dB/ dec. TOHZ rinputsigna a If u is lotimes large distoction occuer. output signal.