Question

1. What is the minimum voltage change that the ADC can detect (the resolution) for a voltage swing of 0VDC to 5VDC? To 10VDC? To 2VDC?

2. What are the maximum voltage input values that the ADC can handle? What should you do if you need to read voltages that are above the maximum voltage inputs?

3. How many output values are possible with an n-bit A/D converter? Why would one choose an 8-bit ADC over a 10-bit ADC? Why would one choose a 10-bit ADC over an 8-bit ADC?

Answer 1

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AAnswer 2 :

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PART 1: Practically maximum input values of ADC is 3.3 volts.

PART 2 : let's say ADC has ab internal voltage reference and we want to measure higher than that. We can use a voltage divider on the inputs to limit my max input signal to said vol. Reference. I can use an external reference that matches my maximum input signal.

We can't change hardware, but we can use voltage divider.

Answer 3 :

there are 2n input values possible with an A/D converter.

About preference of 8 bit and 10 bit ADC :-

An 8 bit ADC had capability to give output till 256 different values and A 10 bit ADC Will have capacity to provide 1024 different values output.

So ,

if one choose 8 bits ADC over 10 bits ADC :-

Because

1.8 bit ADC has lower cost as compared to 10 bit .

2. If one has need till 256 bits only then one will save cost by choosing 8 bit ADC.

If one choose 10 bits over 8 bits ADC

THAT'S BECAUSE

1. 10 bits ADC will have higher resolution, and hence it will provide better precision in comparison to 8 bit ADC.

2. More accurate and more precise results.