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please showing steps for questions 3,4,5 and 6 please i would appreciate it.
kg the gap of adjacent levels is 4.81 x 10. Problem 3. For a particle of mass m 1.33 x 10 Calculate the force constant. (20.


Problem 3. For a particle of mass m=1.33 x 1026 kg the gap of adjacent levels is 4.81 x 10“). Calculate the force constant. (
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. 7 constat) 3 Given m= 1. 381026 ug. 4€ = 4.81 X10-21 J The gap of adjacent level is AE = Eore - Ex := tw = to a ::ww porn oThe transition occure is DE = E (Photon) how = no = ne - = x= anem = 27 x 3x10 m variomx/1. 67262158x10-27 ng - 855 = 18.54x1

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please showing steps for questions 3,4,5 and 6 please i would appreciate it. kg the gap...
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