Answer.
In order to find out the final product, we need to follow the following steps:
Step-1: Identify the - carbon
1 and 2 are the - carbons of the ketone group while ' is the - carbon of the aldehyde group.
With ring forming reactions, five and six membered rings are preferred and there is a possibility of ring formation if the attacking carbon is 2.
Step-2: An acid-base reaction
Hydroxide functions as a base and removes the acidic - hydrogen bonded to the - carbon and gives the reactive enolate.
Step-3: Nucleophilic attack
B. Bonus (10 pts) Intramolecular Aldol.. о он. CH3
What product results from the intramolecular aldol reaction of 2,5-hexanedione? ů CH3 сн. Accн, сн. Асен, CH3 CH3 o I II III IV V O A. I B. II C. III D. IV E.V
10.(7pts) Draw the mechanism for the following self Aldol Condensation. NaOH,H,O, heat Bonus: 5 pts no partial credit. All correct or nothing. Predict the product and draw a mechanism for the following transformation. Sune NaOET EtOH(solvent)
Retroanalisis: Sintesis: (reaccion Aldol intramolecular seguida por deshidratacion)
which of the following molecules cannot undergo an intramolecular aldol condensation when treated with NaOH Which of the following molecules cannot undergo an intramolecular aldol condensation when treated with NaOH
The sequence of a Michael addition followed by an intramolecular aldol condensation is known 5. as a
Draw the mechanism and product for the Intramolecular Aldol condensation. Assume added at the end of the reaction
whats the mechanism? if possible, please explain the steps intramolecular Aldol о оне Сиз
please answer all of the 4 questions What cyclic product is formed in the intramolecular Aldol condensation when the following compound is treated with aqueous NaOH? OT 11 0 0 IV What is the Aldol addition product formed from reaction of the following compound with itself? ++,C#o Cาถวาย 0 0 0 What is the cyclic product formed in the intramolecular Aldol condensation when the following compound is treated with aqueous NaOH? 08 pod od IV OT O II III O...
Help please!! Intramolecular Aldol condensation 9 numbering is contiguous from L to R А B • Which carbon became the enolate in the ring formation of product A? • Which carbonyl carbon was attacked in the ring formation of product A? • Which carbon became the enolate in the ring formation of product B? • Which carbonyl carbon was attacked in the ring formation of product B?