ice initial temperature = 0oC
0oC -----------------------------------> 37oC
(1) (2)
Q = Q1 + Q2
Q = (Cp x m )ice + (m Cp dT )water
Q = (79.7 cal / g) x ( 1.0 g ) + (1.0 g ) (1.0 cal / g. oC ) x (37 oC)
Q = 79.7 + 37
Q = 116.7 cal
heat = 117 cal
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