Question

Create a C program that: Within main, declares a linear array consisting of 10 double values. You can assign values to the array when it is declared or fill them items manually using scanf () - your choice. Also, declare three doubles: min, max, and average. Then from within main, a function is called. The function should take a pointer to the array declared above and then finds the maximum value, the minimum value, and calculates the average of the values in the array. The values should be "returned" to main from the function using pointers. The function prototype should be something like: void arrayStuff(double x[], int size, double* x, double* y, double* z); where x will be the minimum value, y is the maximum value, and z is the average. (You can changes the specific names if your prefer.) Finally, from within main the array values and the min, max, and average values are printed.

Answer 1

MinMaxAvg.c

#include <stdio.h>
void arrayStuff(double d[],int size, double *x, double *y, double *z);
int main()
{
double d[10] = {10.5,11.5,12,5,5.5,6.6,7.7,88.8,66.6,55.5};
double min, max, average;
arrayStuff(d,10,&min,&max,&average);
printf("Min value is %lf\n",min);
printf("Max value is %lf\n",max);
printf("Average value is %lf\n",average);
return 0;
}

void arrayStuff(double d[],int size, double *x, double *y, double *z)
{
*x = d[0];
*y = d[0];
int i=0;
double sum = 0;
for(i=0;i <size; i++){
if(*x > d[i]){
*x = d[i];
}
if(*y < d[i]){
*y = d[i];
}
sum = sum + d[i];
}
*z = sum/size;
}

Output:

sh-4.3$ gcc -o main *.c sh-4.3$ main Min value is 5.000000 Max value is 88.800000 Average value is 26.970000 sh-4.3$