Question

Write a program that contains a main function, a “double custom_operator_function(int op_type, double x, double y)”, a “double min(double,double)”, a double max(double x,double y), and a double pow(double x, int y). The main function is used to call the custom operator function. Next, the custom operator function calls the min/max/pow functions based on the op_type. From the main, call the custom operator function with the three inputs 1/-3/5, 2/4/5, and 3/4/5. Print the result of each input to screen. i) The custom operator function calls the “min”, “max”, or “pow” function based on the value of the parameter op_type (1=min), (2=max), (3=pow) and returns the result of the called function. The arguments passed to the min/max/pow function are the parameters x and y. ii) Do not use the min, max, and pow functions from the math library.

Please use C programming.

Answer 1

Program:

#include<stdio.h>

//function min()
double min(double x,double y)
{
   if(x<y)
   {
       return x;
   }
   return y;
}

//function max()
double max(double x,double y)
{
   if(x>y)
   {
       return x;
   }
   return y;
}

//function power() as there is built-in function pow(), so to avoid confusion
double power(double x,int y)
{
   double v=1;
   int i;
   for(i=1;i<=y;i++)
   {
       v=v*x; //x is multiplied y times
   }
   return v;
}

//function custom_operator_function
double custom_opreator_function(int op_type,double x,double y)
{
   double m,n,o;
   if(op_type==1)
   {
       m= min(x,y);
   }
   else if(op_type==2)
   {
       n= max(x,y);
   }
   else if(op_type==3)
   {
       o=power(x,y); //there is built-in function pow()
  
   }
}

int main()
{
   int p;
   double i,j,k;
  
   //value for op_type is confined here
   printf("Enter the value for p: 1/2/3-");
   scanf("%d", &p);
  
   printf("Enter the value for i: ");
   scanf("%lf", &i);
  
   printf("Enter the value for j: ");
   scanf("%lf", &j);
      
   k= custom_opreator_function(p,i,j);
   printf("Result: %lf", k);
  
}

Output: