#include <iostream> #include <cmath> using namespace std; int main() { int x; int y; int z;...

Question

Question

#include <iostream>
#include <cmath>

using namespace std;

int main()
{

int x;
int y;
int z;
int r1;
int r2;
cin >> x;
cin >> y;
cin >> z;
r1 = 4* pow(x,3)-5*pow(y,2)+3*z;
r2 = r1+7*pow(x,3)-2*pow(y,2)+11*z;

cout << "r1=";
cout << 4* pow(x,3)-5*pow(y,2)+3*z;
cout << endl;
cout << "r2=";
cout << r1+7*pow(x,3)-2*pow(y,2)+11*z;
cout << endl;
cout << "r3=";
cout << r2-9*pow(x,3)+22*pow(y,2)-6*z;
cout << endl;

return 0;
}

1-115 Your output r2-395 13-186 5:Compare output Output differs. See highlights below. -163 97218 1-1,7235 3--7.271699 1-17235 3--7271690 Input202 Your output 2--4.6562Be+07 Expected output 2-46562 6: Compare output Results hidden by your instructor

engineering Computer-Science

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Answer 1

Answer #1

// Sample Output
   -163
   -202
   97218
 
r1=-17235354
r2=-46562793
r3=-7271690

// Code

#include <iostream>

#include <cmath>

using namespace std;

int main()

{

int x;

int y;

int z;

int r1;

int r2;

cin >> x;

cin >> y;

cin >> z;

r1 = 4* pow(x,3)-5*pow(y,2)+3*z;

r2 = r1+7*pow(x,3)-2*pow(y,2)+11*z;

cout << "r1=";

int one = 4* pow(x,3)-5*pow(y,2)+3*z;

cout << one;

cout << endl;

cout << "r2=";

int two = r1+7*pow(x,3)-2*pow(y,2)+11*z;

cout << two;

cout << endl;

cout << "r3=";

int three = r2-9*pow(x,3)+22*pow(y,2)-6*z;

cout << three;

cout << endl;

return 0;

}

Add a comment

Answer 2

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