Question

A gas mixture consisting of count:70%H2,20%N2, and 10% O2, Calculate A)Heat capacity of the molecular mixture(Cpmix) B) Molec

Cp CH4=3.204+0.0018T(Cp in cal/gmolk, I in K) Cp H2=6.946-0.196X10-3T(Cp in cal/gmolk,T in K) Cp N2=6.547-1.389X10-3T(Cp in c

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Answer #1

1-355 Gos mixture. 701 H 207 N₂ , 10% O₂. PH = 6.946-0-1968103 T/C Cppy = 6-847-1.389 410²t (cd/gml x) Cpuun = 3.904+0.0018 TGE Q=0.93010°321165 - 0-741390 4900]) -0.480 KIO 39-165166147 =0-9801103295507 1Q=22099 Kcal/hout . Now, This much of heat

Using 1st law of thermodynamics we can calculate the Cpmix Mbmix & steam required for heating & amount of heat required.

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