Question

For the beam illustrated in the figure, find the locations and magnitudes of the maximum tensile bending stress due to Mand the maximum shear stress due to V. The parameters are a = 4,5 in, b = 14,5 in, c = 0.775 in, h = 2.2 in, 6 = 3000 lbf, and F2 = 1100 lbf. Filbi F2ib cin a in A A bin R Ain h in The moment of inertia is in4 The maximum tensile bending stress due to Mis psi. The maximum shear stress due to Vis psi.

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Answer 1

FBD 3000 lbf 1100 lbf В 4.59 12 14.5 12-21 R R2 0.775 Solving for forces, Ofy zo = R + R₂ = 4100 lbf EMA=0 » R2*14.5 = 1100*19 - R2 = 1441.38 167 So R, = 2658.62 lbf Shear force V at point c. Ve = 1100 lbf V at point B, Vg = 1100 - 1441.38 = - 341.38 Ibt vat point A VA 1100 - 144138 + 3000 - 2658.62 = 01b/. Bending Moment M at point c, Mc = 0 lbf.in M at point MB = 11004.5 = 4950 lbt.in Mat point A MA= 1100x19 - 1441.38x14.5 = 0 lbfin. Mo =0. Maximum bending Moment is at point B. Mnay = 4950 lbfin

a) Moment of Pregtia, I = bd3 chi ! 12 12 3 >) P = 0.77542.2 I= 0.6877 in4 Ans 12 an Ma omax = 4950x6 MAX = 4950x ch% L 0.775*2.22 max 7917.88 psi Ans 1600 e) Average Shear Stress = Vman Area 645.16 psi 0.725X2.2 Max Shear stress = 3 x Average Shear Stress - à x 645.16 ~) [max = 967.74 psi Ang
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