The perimeter of a rectangle is 30. The dimensions are unknown.Write an eauation that gives the...
The perimeter of a rectangle is 30. The dimensions are unknown.Write an eauation that gives the length, y, in terms of the width, x . Complete the table of values to help you.
Width.(x)
Length(y)
1.
2.
3.
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The perimeter of a rectangle is 30. The dimensions are
unknown.Write an eauation that gives the...
The length and width of a rectangle must have a sum of 30. Find the dimensions...
The length and width of a rectangle must have a sum of 30. Find the dimensions of the rectangle that will have the maximum area. [hint: let x and 30-x be the length and width] the area can be described by the function f(x)=x(30-x).]
If the perimeter of a rectangle is 40 cm and the area is 84 square cm,...
If the perimeter of a rectangle is 40 cm and the area is 84 square cm, then what are the dimensions of the rectangle? The width, or shorter side is ___cm The length, or longer side is ____ cm
If the perimeter of a rectangle is 48 cm and the area is 140 square cm,...
If the perimeter of a rectangle is 48 cm and the area is 140 square cm, then what are the dimensions of the rectangle? The width, or shorter side is cm The length, or longer side is cm
If the perimeter of a rectangle is 50 cm and the area is 156 square cm,...
If the perimeter of a rectangle is 50 cm and the area is 156 square cm, then what are the dimensions of the rectangle? The width, or shorter side is___ cm The length, or longer side is ___ cm
If the perimeter of a rectangle is 34 cm and the area is 72 square cm,...
If the perimeter of a rectangle is 34 cm and the area is 72 square cm, then what are the dimensions of the rectangle? The width, or shorter side is ___ cm The length, or longer side is___ cm
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Solve the problem. The width of a rectangle is fixed at 30 cm, and the perimeter...
Solve the problem. The width of a rectangle is fixed at 30 cm, and the perimeter can be no greater than 170 cm Find the sm rectangle maximum length of the Select one: O a. 70 cm O b. 55 cm O c. 110 cm O d. 140 cm
You may remember that the perimeter of a rectangle is P=2(W+L) where W is the width...
You may remember that the perimeter of a rectangle is P=2(W+L) where W is the width and L is the length. Suppose that the perimeter of a rectangle is 44 feet, and the length is 12 feet more than the width. Find the width of the rectangle, in feet.
If the perimeter of a rectangle is 48 cm and the area is 140 square cm, then what are the dimensions of the rectangle? The width, or shorter side is cm The length, or longer side is cm
Solve the problem. The width of a rectangle is fixed at 30 cm, and the perimeter can be no greater than 170 cm Find the sm rectangle maximum length of the Select one: O a. 70 cm O b. 55 cm O c. 110 cm O d. 140 cm
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