47. Calculate the rotational inertia (kg* m^2) of a wheel that has kinetic energy of 15,000J when rotating at 502 rpm. (in kg*m^2)
angular speed, w = 502 rpm
= 502*2*pi/60 rad/s
= 52.54 rad/s
we know, Rotational Kinetic enrgy, KE = 0.5*I*w^2
===> I = 2*KE/w^2
= 2*15000/52.54^2
= 10.87 kg.m^2 <<<<<<<<<-----------Answer
47. Calculate the rotational inertia (kg* m^2) of a wheel that has kinetic energy of 15,000J...
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