4)
without prior estimate, let sample proportion
, p̂ = 0.5
sampling error , E =
0.03
Confidence Level , CL=
0.90
alpha = 1-CL = 0.1
Z value = Zα/2 =
1.645 [excel formula =normsinv(α/2)]
Sample Size,n = (Z / E)² * p̂ * (1-p̂) = (
1.645 / 0.03 ) ² *
0.50 * ( 1 - 0.50 ) =
751.5398
so,Sample Size required=
752
5)
µ = 73.06
σ = 0.11
proportion= 0.9200
proportion left 0.0800 is equally
distributed both left and right side of normal
curve
z value at 0.04 = ±
1.751 (excel formula =NORMSINV(
0.08 / 2 ) )
z = ( x - µ ) / σ
so, X = z σ + µ =
X1 = -1.751 * 0.11
+ 73.06 =
72.87
X2 = 1.751 * 0.11
+ 73.06 =
73.25
answer: (72.87 , 73.25)
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